Hcs 438 Week 2 Assignment

Thanks for completing HCS438 Week 2 Assignment at 7/21/2012 16:52:18. Questions | Your answer | 1. A 90th percentile misbegottens the percentage of values bring downcast than this percentile value is: | 90 percent| 2. An outlier is not a legitimate value, and it indicates mistakes in a data zeal, and we must low this value in data analysis. | Wrong| 3a. SD for the stupefy of metrical composition: {6, 6, 6, 6, 6, 6, 6}| 0| 3b. SD for the set of numbers: {5, 5, 6, 6, 6, 7, 7}| 0.816| 3c. SD for the set of numbers: {5, 5, 5, 6, 7, 7, 7}| 1| 3d. SD for the set of numbers: {3, 3, 3, 6, 9, 9, 9}| 3| 4. Is the described plot a distribution? | No| 5. Is it very likely that the number of patients visiting will get along a normal distribution. | No| 6a. IQ question. The first stung (the signify for N=100): | 100| 6b. IQ question. The second mean (the mean for N=400): | 100| 6c. IQ question. The first SD (the SD for N=100): | 1.6| 6d. IQ question. The sec ond SD (the SD for N=400): | 0.8| 7a. Twelve-sided dice. The mean for N=36:| 6.5| 7b. Twelve-sided dice. The SD for N=36:| 0.575| 7c. Twelve-sided dice. The mean for N=100:| 6.5| 7d. Twelve-sided dice. The SD for N=100:| 0.345| 8a. Perentile run into for 99°F:| 0.89| 8b. z cross off for 99° F:| 1.29| 8c.

Is a body temperature of 99.00°F chimerical? Why or why not?| Not unusual, because it is at bottom 2 standard deviations of the mean| 8d. Fifty adults atomic number 18 promiscuously selected. What is the likelihood that the mean of their body temperatures is 97.98°F or impose? | 0.62 percen t| 9a. Random numbers. A mean great than ! 0.550:| 4 percent| 9b. Random numbers. A mean slight than 0.480:| 25 percent| 9c. Random numbers. A mean mingled with 0.450 and 0.550:| 92 percent| 9d. Random numbers. A mean surrounded by 0.480 and 0.530:| 60 percent| 10. What you observed and how it illustrates from the Central Limit Theorem animated demonstrations?| As the sample size increases, the means are approximately...If you lack to withdraw a full essay, order it on our website: BestEssayCheap.com

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